I was going throught the question that what is the minimum batch size required in a system to ensure that two people at least have the same birthdays and did a simulation of that in excel.
However, I thought that if we can have a maxima or minima funda in P(n)=1-365!/(365-n)!*365^n we can find the value of n.
The answer is 50 approx.
Let us see.
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- I am a risktaking aries maverick (not risque otherwise) who doesn't believe in the idea of settling and committing. Small wonders I am not settled and committed so far. There is no 'Lakshmi' in my kundli. Ergo, I am known as 'Garibdas'. I am a techno savvy 'khalihar'. I tried emulating Howard Roark but ended up with a status below that of a common man. Nonetheless, offer me a drink and I will be in my elements and I promise you a full 'paisa-wasool'. I would love to be a truly free freelancer in anything. I will prefer dabbling with my work all my life. I doubt if I desperately need companionship in the form of spouse. But I am sure that I am an old man now. I prefer an upcountry mofussil town to work vis-a-vis any 'fury' metro and will try to do a course in rural management anytime in my life. And yes, I love my familiar surroundings a lot. I will simply die without them. When I was born, God told me that he will allow me to ' aish maro' only in one quarter of the century of an age. I chose the first 25 years. Which is why, the subsequent quarters are devoid of everything. However, I should not be having any qualms about this because it was apun ka choice.:)
2 comments:
shouldn't the batch size be 366 for normal years and 367 for leap years?
How come it can be 50??
Kindly enlighten me on this... :-)
try it for any group sixe of 50 and you will get it...
i ll try to explain the rationale very soon...
thanx for the inquisitiveness!
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